Simple Equations : Q2 : Solns

The sum of 4 consecutive numbers of same month should be x + x+1 + x+2 + x+3 = 4x+6 and it should also be in form of 2^N. Any no in form of 4x+6 cant be a power of 2. Therefore days are consecutive but from different months.
The powers of 2 are 1, 2, 4, 8, 16, 32, 64, 128.

The minimum possible value that 4 consecutive days can take is 27+28 + 1 + 2 = 58

So only sum possible here is 64

We can obtain 64 by adding 30 + 31 + 1 + 2 = 64
We can eliminate 1, 2, 4, and 8 since sum of 4 consecutive integers is always greater than 9.
So we cumulative spending is 2^N = 64 = 2^6

So answer is 6 , hence option B